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Write a Pythagorean triplet whose smallest member is 8 |
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Answer» ANSWER: 8, 15, 17 Step-by-step explanation: Pythagoras triplets are of the form. 2m, m² -1 and m² + 1. It is GIVEN that SMALLEST number is 8. So, 2m = 8. m = 4. Now, second number = m² -1 = 4² - 1 = 15. and, third number = m² + 1 = 4² + 1 = 17. Hence, the TRIPLET is 8, 15 and 17. Verification :- 17² = 8² + 15² 289 = 64 + 225 289 = 289. Please brainlist my answer, if helpful! |
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