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Write a Pythagorean triplet whose smallest member is 6. |
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Answer» Given 6 is the smallest number in Pythagorean triplet But we have for every number m>1, we have (2m, m2-1, m2+1) as a Pythagorean triplet Using the above condition we can write as 2m = 6 m=6/2=3 Then m2 = 9 m2 – 1 = 9 – 1 = 8 m2 + 1 = 9 + 1 =10 Therefore the Pythagorean triplet is = (2m, m2-1, m2+1) = (6, 8, 10) |
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