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Write a Pythagorean triplet whose smallest member is 20. |
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Answer» Given 20 is the smallest number in Pythagorean triplet But we have for every number m>1, we have (2m, m2-1, m2+1) as a Pythagorean triplet Using the above condition we can write as 2m = 20 m= 20/2=10 Then m2 =100 m2 – 1 = 100 – 1 = 99 m2 + 1 = 100 + 1 =101 Therefore the Pythagorean triplet is = (2m, m2-1, m2+1) = (20, 99, 101) |
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