Saved Bookmarks
| 1. |
Write a Pythagorean triplet whose smallest member is 16. |
|
Answer» Given 16 is the smallest number in Pythagorean triplet But we have for every number m>1, we have (2m, m2-1, m2+1) as a Pythagorean triplet Using the above condition we can write as 2m = 16 m= 16/2=8 Then m2 =64 m2 – 1 = 64 – 1 = 63 m2 + 1 = 64 + 1 =65 Therefore the Pythagorean triplet is = (2m, m2-1, m2+1) = (16, 63, 65) |
|