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Write a Pythagorean triplet whose smallest member is 14. |
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Answer» Given 14 is the smallest number in Pythagorean triplet But we have for every number m>1, we have (2m, m2-1, m2+1) as a Pythagorean triplet Using the above condition we can write as 2m = 14 m= 14/2=7 Then m2 =49 m2 – 1 = 49 – 1 = 48 m2 + 1 = 49 + 1 =50 Therefore the Pythagorean triplet is = (2m, m2-1, m2+1) = (14, 48, 50) |
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