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working together a b and c completes the work in 24 days after working together a left the work after 4 days .a and b completes remaining work in 30 days .how many days taken by c to completes the work alone |
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Answer» ong>Answer: one days WORK of each of A,B and C is 1/24 =5/120 ,1/30=4/120 and 1/40=3/120 respectively so that their one days work when all THREE work together is (5/120)+(4/120)+(3/120)=12/120 =1/10 TH part of the whole work so they all together can complete the work in 120/12 =10 days C left 4 days before MEANS 4 x 1/10 = 4/10 part of work is left A and B s one days work is 5/120 + 4/120 =9/120 th part so they can complete whole the work in 120/9 days and they can complete 4/10 th part of work in 4/10 x120/9 =16/3 days or 5+ (1/3) days total work will be completed in 6+ 5+(1/3)=11+(1/3) days |
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