Work of 3.0xx10^(-4) Joule is required to be done in increasing the size of a soap film from 10cmxx6cm to 10cmxx11cm. The surface tension of the film is ……

Work of 3.0xx10^(-4) Joule is required to be done in increasing the si

1.	Work of 3.0xx10^(-4) Joule is required to be done in increasing the size of a soap film from 10cmxx6cm to 10cmxx11cm. The surface tension of the film is ……
Answer» `5xx10^(-2)N//m` `3xx10^(-2)N//m` `1.5xx10^(-2)N//m` `1.2xx10^(-2)N//m` Solution :Surface tension T`=("work DONE")/("INCREASE in AREA")` Soap film has two free surface , `thereforeT=(3.0xx10^(-4)J)/(2XX(10xx11-10xx6)xx10^(-4))` `=3xx10^(-2)(N)/(m)`