Saved Bookmarks
| 1. |
Work done in the cyclic process shown in figure is PA3P.POV.• V3V.(2) 4P.V.(0,0)(1) 4P.V.22(3) EPVO7(4) -13P.V. |
|
Answer» tion:As we linow that area under p−v CURVE GIVES worle done. as we KNOW that area of circle is given as =πr2 but kere The que of curve is given asA=πr1γ2Where γ1=3v0−V02=2v0v2γ1=v0γ2=3p0−P02=P0 γ1=v0;r2=p0 Work done =−πγ1Y2abecouse circle 15 anticlockwise=−πv0p0πv0p0{π=227}Work =−227 POVO Aus0,7+π/3 |
|