1.

Work done by restoring force in a wire within elastic limit is -10j maximum amount of heat produced ?

Answer»

As PER thermodynamics LAW, \Delta Q=\Delta <klux>U</klux>+\Delta W

where \Delta Q heat energy absorbed/released, [tex]\Delta U is changed in internal energy and [tex]\Delta W is work done.Restoring force acts so quickly, there will be negligible heat loss. Hence we approximate this process as adiabatic and \Delta Q = 0Hence we have, [tex]\Delta U+\Delta W=0, since \Delta W = -10 J, we have \Delta U = 10 J.



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