Work done by a force F = yi + xj as the particle istaken from (1, 2) t

1.	Work done by a force F = yi + xj as the particle istaken from (1, 2) to (3, 4) is
Answer» Work was done ∫FdtWhen particle MOVES from 0 to a along x-axisThen W1=∫0a−(KYI)dx=0 ∵y=0Now, when the particle moves PARALLEL to the y-axisW2=∫0a−(KAJ)dy ∵x=a∴W2=−Ka∫0ady=−Ka2∴W=W1+W2=−Ka2Explanation:I hope it will be help you

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Work done by a force F = yi + xj as the particle istaken from (1, 2) to (3, 4) is​

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Work done by a force F = yi + xj as the particle istaken from (1, 2) to (3, 4) is