without solving the following quadratic equation find the value of p f

1.	without solving the following quadratic equation find the value of p for which the given equation has real and equal roots x^2 + (p-3)x +p =0
Answer» Answer:X2 + (p - 3) x + p = 0 Here, A = 1, B = (p - 3), C = p Since, the roots are real and equal, D = 0 B2 - 4ac = 0 (p - 3)2 - 4(1) (p) = 0 p2 + 9 - 6p - 4p = 0 p2 - 10P + 9 = 0 (p - 1)(p - 9) = 0 p = 1 or p = 9 Step-by-step explanation:

without solving the following quadratic equation find the value of p for which the given equation has real and equal roots x^2 + (p-3)x +p =0

Answer»

Answer:X2 + (p - 3) x + p = 0

Here, A = 1, B = (p - 3), C = p

Since, the roots are real and equal, D = 0

B2 - 4ac = 0

(p - 3)2 - 4(1) (p) = 0

p2 + 9 - 6p - 4p = 0

p2 - 10P + 9 = 0

(p - 1)(p - 9) = 0

p = 1 or p = 9

Step-by-step explanation:

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without solving the following quadratic equation find the value of p for which the given equation has real and equal roots x^2 + (p-3)x +p =0​

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without solving the following quadratic equation find the value of p for which the given equation has real and equal roots x^2 + (p-3)x +p =0