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Without solving the equation find tue value of p for which the equation (p-3)x2 -2(p-3)x+2 |
Answer» ANSWERP = 3 & 5EXPLANATION1) =TO FIND value of p2)= solution(p-3) x^2 - 2(p-3)x +2D =b^2 - 4ac= > 4(p-3)^2 - 4(p-3)(2)=0= > 4(p^2 +9 - 6p) - 8p+24 =0= > 4p^2 + 36 -24p - 8p + 24 = 0= > 4p^2 - 32p + 60 =0= > p^2 - 8p + 15 =0= > p^2 - 5P - 3p + 15 =0= > p(p - 5) - 3(p - 5) = 0= > (p - 3) ( p - 5) =0= > p = 3 & p = 5 |
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