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Without changing the direction of coordinate axes, origin is transferred to (h, k), so that the linear (one degree)terms in the equation x2+y2−4x+6y−7=0 are eliminated. Then the point (h, k) is |
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Answer» Without changing the direction of coordinate axes, origin is transferred to (h, k), so that the linear (one degree) terms in the equation x2+y2−4x+6y−7=0 are eliminated. Then the point (h, k) is |
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