1.

With what least number must 8640 be divided so that the quotient is a perfect cube

Answer»

5 is the smallest NUMBER that 8640 must be divided with so that the QUOTIENT is a perfect cube.

Step-by-step explanation:

As we know,

PRIME Factorization of 8640 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5

= 2^{3} * 2^{3} * 3^{3} * 5

In this factorization, the triplets of 2 and 3 but not of 5.

So,

5 is the smallest number by which 8640 should be divided so that the quotient is a perfect cube.

Learn more: find the LEAST number divisible

brainly.in/question/9752524



Discussion

No Comment Found

Related InterviewSolutions