With what acceleration must the breaks be applied to stop a vehicle tr

1.	With what acceleration must the breaks be applied to stop a vehicle travelling with a speed of 40km/he in 20 seconds
Answer» Answer: -0.555 m/s^2 Explanation: According to the GIVEN question, u = initial velocity = 40 km/h = 40×1000/3600 = 11.1 m/s t = time = 20 sec v = FINAL velocity = 0 m/s a = acceleration and -a = deceleration And we are asked to find the RETARDATION or deceleration of the vehicle. We know, v = u+at Putting the values we get 0 = 11.1+ 20 a 20a = -11.1 a = -11.1/20 a = - 0.555 m/s^2 Thus declaration of the vehicle should be 0.5 m/s^2 (approx) in 20 sec to stop the vehicle TRAVELING with 40 km/h . Means acceleration should be -0.5 m/s^2.

With what acceleration must the breaks be applied to stop a vehicle travelling with a speed of 40km/he in 20 seconds

Answer»

Answer:

-0.555 m/s^2

Explanation:

According to the GIVEN question,

u = initial velocity = 40 km/h = 40×1000/3600 = 11.1 m/s

t = time = 20 sec

v = FINAL velocity = 0 m/s

a = acceleration and -a = deceleration

And we are asked to find the RETARDATION or deceleration of the vehicle.

We know,

v = u+at

Putting the values we get

0 = 11.1+ 20 a

20a = -11.1

a = -11.1/20

a = - 0.555 m/s^2

Thus declaration of the vehicle should be 0.5 m/s^2 (approx) in 20 sec to stop the vehicle TRAVELING with 40 km/h .

Means acceleration should be -0.5 m/s^2.

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With what acceleration must the breaks be applied to stop a vehicle travelling with a speed of 40km/he in 20 seconds

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