With the help of Avogadros law, show that the volume of one mole of an

1.	With the help of Avogadros law, show that the volume of one mole of any gas at STP is always 22.414dm^3plz answer fast
Answer» Answer: According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and CONTAINS avogadro's number $6.023\times 10^{23}$ of particles. Standard CONDITION of temperature (STP) is 273 K and ATMOSPHERIC pressure is 1 atmosphere RESPECTIVELY. According to the ideal gas equation: $PV=nRT$ P = Pressure of the gas = 1 atm V= Volume of the gas = ? T= Temperature of the gas = 273 K R= Gas constant = 0.0821 atmL/K mol n= moles of gas= 1 $V=\frac{nRT}{P}=\frac{1\times 0.0821\times 273}{1}=22.4L$ Thus at STP one mole of gas occupies a volume of 22.4 liters.

With the help of Avogadros law, show that the volume of one mole of any gas at STP is always 22.414dm^3plz answer fast

Answer»

Answer:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and CONTAINS avogadro's number $6.023\times 10^{23}$ of particles.

Standard CONDITION of temperature (STP) is 273 K and ATMOSPHERIC pressure is 1 atmosphere RESPECTIVELY.

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 1 atm

V= Volume of the gas = ?

T= Temperature of the gas = 273 K

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= 1

$V=\frac{nRT}{P}=\frac{1\times 0.0821\times 273}{1}=22.4L$

Thus at STP one mole of gas occupies a volume of 22.4 liters.