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With resistances P and Q in the left gap and right gap respectively, of a meter bridge. The null point is obtained at 60 cm from left end. When Q is increased by `10Omega` the null point is obtained at 40 cm from left end. The values of P and Q areA. `12Omega, 8Omega`B. `8Omega, 12Omega`C. `8Omega, 8Omega`D. `12Omega, 12 Omega` |
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Answer» Correct Answer - A (i) `(P)/(Q)=(60)/(40) " " P=(3Q)/(2)` (ii) `(P)/(Q+10)=(40)/(60)` `(3Q)/(20+20)=2/4 " " 9Q=4Q+40 " " 5Q=40` `:.P=(3xx8)/(2)=12Omega` |
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