1.

With resistances P and Q in the left gap and right gap respectively, of a meter bridge. The null point is obtained at 60 cm from left end. When Q is increased by `10Omega` the null point is obtained at 40 cm from left end. The values of P and Q areA. `12Omega, 8Omega`B. `8Omega, 12Omega`C. `8Omega, 8Omega`D. `12Omega, 12 Omega`

Answer» Correct Answer - A
(i) `(P)/(Q)=(60)/(40) " " P=(3Q)/(2)`
(ii) `(P)/(Q+10)=(40)/(60)`
`(3Q)/(20+20)=2/4 " " 9Q=4Q+40 " " 5Q=40`
`:.P=(3xx8)/(2)=12Omega`


Discussion

No Comment Found

Related InterviewSolutions