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Will AgCl be more soluble in aqueous solution or NaCl solutions and why ? |
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Answer» `AgCl hArr Ag^(+) + Cl^(-)` In NaCl solution, `[Cl^(-)]` will increase. As `[Ag^(+)][Cl^(-)]=K_(sp)` remains constant, `[Ag^(+)]` will decrease, i.e., the solubility will be less in NaCl solution than in water. |
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