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Why Tan²¤ + 1 = Sec²¤​

Answer»

Here Is Your Ans

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BY PYTHAGORAS Theorem

h² = p² + b² ---- 1

Divide b² In equation 1

= > \frac{ {h}^{2} }{b} = \frac{ {p}^{2} }{ {b}^{2} } + \frac{ {b}^{2} }{ {b}^{2} } \\ \\ = > {( \frac{h}{b} )}^{2} = {( \frac{p}{b} )}^{2} + {( \frac{b}{b} )}^{2} \\ \\

=> Sec²¤ = Tan²¤ + 1

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