Why kmno4 is strong oxidizing agent in acidic medium?

1.	Why kmno4 is strong oxidizing agent in acidic medium?
Answer» <STRONG>We know that In KMnO₄ the Mn CHARGE = +7, On writing the reaction in acidic , neutral and basic medium. (i)So reaction OCCURS in acidic medium :- _______________________ *MnO₄⁻ + 8 H⁺ + 5 e⁻ ----→ Mn²⁺ + 4H₂O* _______________________ As you see here , Mn gives up 5 e⁻ . (Making this as a strong oxidizing agent) (ii) So reaction occurs in Neutral medium :- _____________________ *MnO₄⁻ + 4H⁺ + 3 e⁻ ------→ MnO₂ + 2H₂O* _____________________ As you can see here , In this neutral SOLUTION, it gives up 3 e⁻ in formation of MnO₂ & also some OH ions. (ii) So reaction occurs in Basic medium :- _____________________ *MnO₄⁻ + e⁻ -----→ MnO₄²⁻* _____________________ As you can see here, it only gives up 1 e⁻ , So it makes it weaker oxidizing agent. Hence we can simply observe here :- MnO₄⁻ ion → Acidic solution > Neutral solution > Basic solution. Hence it is strong oxidising agent in acidic medium. *Hope it Helps :-)*

Answer»

<STRONG>We know that In KMnO₄ the Mn CHARGE = +7,

On writing the reaction in acidic , neutral and basic medium.

(i)So reaction OCCURS in acidic medium :-

_______________________

MnO₄⁻ + 8 H⁺ + 5 e⁻ ----→ Mn²⁺ + 4H₂O

_______________________

As you see here , Mn gives up 5 e⁻ . (Making this as a strong oxidizing agent)

(ii) So reaction occurs in Neutral medium :-

_____________________

MnO₄⁻ + 4H⁺ + 3 e⁻ ------→ MnO₂ + 2H₂O

_____________________

As you can see here , In this neutral SOLUTION, it gives up 3 e⁻ in formation of MnO₂ & also some OH ions.

(ii) So reaction occurs in Basic medium :-

_____________________

MnO₄⁻ + e⁻ -----→ MnO₄²⁻

_____________________

As you can see here, it only gives up 1 e⁻ , So it makes it weaker oxidizing agent.

Hence we can simply observe here :-

MnO₄⁻ ion → Acidic solution > Neutral solution > Basic solution.

Hence it is strong oxidising agent in acidic medium.

Hope it Helps :-)

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