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Why equilibrium constant is related to `E_("cell")^(c-)` but not to `E_("cell")` ?

Answer» At equilibrium, `E_(cell)=0`, whereas `E_("cell")^(c-)` is a constant quantity. Hence, `E_("cell")^(c-)=(RT)/(nF)lnK_(c)=(0.059)/(n)logK_(c)`


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