White phosphorous is a tetra atomic solid [P4(s)] at room temperature and on strong heating in absence of oxygen, it polymerizes into red phosphorus as: ΔH=−104 kJ/mol of P4 The enthalpy of sublimation [P4(s)→P4(g)] white is 59 kJ/mol and enthalpy of atomization is 316.25 kJ/mol of P(g). Now find the average P−P bond enthalpy in P4 molecule is:

White phosphorous is a tetra atomic solid [P4(s)] at room temperature

1.	White phosphorous is a tetra atomic solid [P4(s)] at room temperature and on strong heating in absence of oxygen, it polymerizes into red phosphorus as: ΔH=−104 kJ/mol of P4 The enthalpy of sublimation [P4(s)→P4(g)] white is 59 kJ/mol and enthalpy of atomization is 316.25 kJ/mol of P(g). Now find the average P−P bond enthalpy in P4 molecule is:
Answer» White phosphorous is a tetra atomic solid $[P_{4} (s)]$ at room temperature and on strong heating in absence of oxygen, it polymerizes into red phosphorus as: $Δ H = - 104 kJ/mol of P_{4}$ The enthalpy of sublimation $[P_{4} (s) \to P_{4} (g)]$ white is $59 kJ/mol$ and enthalpy of atomization is $316.25 kJ/mol$ of $P (g)$ . Now find the average $P - P$ bond enthalpy in $P_{4}$ molecule is: