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While performing a thermodynamics experiment, a student made the following observations, HCl + NaOH → NaCl + H2O ΔH = –57.3 kJ mol–1 CH3COOH + NaOH → CH3COONa + H2O ΔH = –55.3 kJ mol–1. The enthalpy of ionization of CH3COOH as calculated by the student is ______ kJ mol–1. (nearest integer) |
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Answer» ΔHionisation of CH3COOH = |-57.3 - (-55.3)| = 2 KJ/mol |
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