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While measuring the diameter of a lead-shot using a screw gauge , the reading on the pitch scale is found to be 7.5 mm and that on the head scale is 48 . If the least count is 0.01 mm and zero error is +0 l. 05 mm , find the diameter of the lead-shot . |
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Answer» Answer: Here is your answer P. S. R = 7.5 mm H. S. R = 48 L. C = 0.01 mm Error = +0.05 mm , correction = -0. 05 mm Diameter of lead-shot = P. S. R + H. S. R × L. C + Correction => 7.5 mm + 48 × 0.01 mm - 0.05 mm => 7.98 mm - 0.05 mm => 7.93 mm The diameter of the lead shot is 7.93 mm. |
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