1.

Which value of k the linear equation have no solution 2x - ky + 4 = 0 12x + 8y + 10 = 0​

Answer»

Step-by-step explanation:

Given

2x+ky+k+2=0

kx+8y+3k=0

For equation to be inconsistent,

a

2

a

1

=

b

2

b

1

=

c

2

c

1

Where a

1

,a

2

are X coefficients

b

1

,b

2

are y coefficients

c

1

,c

2

are constants

k

2

=

8

k

=

3k

k+2

k=±4 and

3k

2

=8K+16

3k

2

−8k−16

=0

3k(k−4)+4(k−4)

=0

k

=4 and k

=

3

−4

k=−4 the given system of EQUATIONS are inconsistent


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