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which term of the following progression 0.00 4010 20.1 is 128 |
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Answer» It is a geometric progression with common ratio, r=5 ; and first term, a=0.004 the nth term of a geometric progression is given by, an = a(r)n-1 for the given question we have, an=128 Hence, 128=0.004(5)n-1 32000=5n-1 Taking log with base 5 on both sides 6.445=n-1 n=7.445 Since n is not a natural number we can conclude that 128 is not a term of the series. |
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