Which term of the AP 8, 14, 20, 26---- will be 72 more than its 41 st

1.	Which term of the AP 8, 14, 20, 26---- will be 72 more than its 41 st term?
Answer» ANSWER:- $\sf \huge \: AP:8,4,20,26.... \\ \: \\ \\ \sf \huge \mapsto \: a=8 \\ \\ \sf \huge \mapsto \: d=14-8=6 \\ \\ \bf \huge \: Let T_n=T_41+72 \\ \\ \tt \huge \longmapsto \: a+(n-1)d-a-40d=72 \\ \\ \tt \huge \longmapsto \:d(n-1-40)=72 \\ \\ \tt \huge \longmapsto \:6(n-41)=72 \\ \\ \tt \huge \longmapsto \:n-41=12 \\ \\\tt \huge \longmapsto \: n=12+41 \\ \\ \tt \huge \longmapsto \:n=53 \\ \\ \bf \huge \bigstar \: Required \: \: term \: \: is \: \: 53 \\ \\ \bf \huge \bigstar \:53 \: th \: \: term \: \: of \: \: AP \: \: will \: \: be \: 72 \: \: more \: \: than \: \: 41 \: \: th \: \: term.....$

Which term of the AP 8, 14, 20, 26---- will be 72 more than its 41 st term?

Answer»

ANSWER:-

$\sf \huge \: AP:8,4,20,26.... \\ \: \\ \\ \sf \huge \mapsto \: a=8 \\ \\ \sf \huge \mapsto \: d=14-8=6 \\ \\ \bf \huge \: Let T_n=T_41+72 \\ \\ \tt \huge \longmapsto \: a+(n-1)d-a-40d=72 \\ \\ \tt \huge \longmapsto \:d(n-1-40)=72 \\ \\ \tt \huge \longmapsto \:6(n-41)=72 \\ \\ \tt \huge \longmapsto \:n-41=12 \\ \\\tt \huge \longmapsto \: n=12+41 \\ \\ \tt \huge \longmapsto \:n=53 \\ \\ \bf \huge \bigstar \: Required \: \: term \: \: is \: \: 53 \\ \\ \bf \huge \bigstar \:53 \: th \: \: term \: \: of \: \: AP \: \: will \: \: be \: 72 \: \: more \: \: than \: \: 41 \: \: th \: \: term.....$

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