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Which term of the AP: 3,15,27,39,.....will be 132 more than its 54th term?? |
| Answer» let the required term be nth term54th term = a +(n-1)d\xa0= 3 + 53x12 = 3 + 636 = 639therefore 132 + 639 = 771 will be the nth term.771 = 3 + (n-1)12768/12 +1 = ntherefore n = 64\xa0+1 = 65therefore the 65th term will be 132 more than the 54th term | |