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Which term of the AP 3, 15, 27, 39, .... will be 144 more than its 54th term ?​

Answer»

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3, 15, 27, 39…….

an=a+(n−1)d

a=3,d=15−3=12

n=54

a54=a+(n−1)d

=3+(54−1)×12

=3+53×12

=639

TERM which is 144 more than its 54th term is – 639 + 144 = 783

an=773

783=a+(n−1)d

783=3+(n−1)12

783-3=12n-12

780+12=12n

792=12n

n=792/12

n=66


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