Which term of the AP: 3. 15, 27, 39,will be 132 morethanits54thterm?nl

1.	Which term of the AP: 3. 15, 27, 39,will be 132 morethanits54thterm?nlan olie hetween 10 and 250?
Answer» For an AP 3, 15, 27, 39a = 3, d = 15-3 = 12 nth terman = a + (n - 1)da54 = 3 + 5312a54 = 639 Let mth term of an AP= 639 + 132 = 771 Then,771 = 3 + (m - 1)12771 = 3 + 12m - 12771+9 = 12m780 = 12 mm = 780/12 = 65 Therefore 65th term is 132 more than 54th term

Which term of the AP: 3. 15, 27, 39,will be 132 morethanits54thterm?nlan olie hetween 10 and 250?

Answer»

For an AP 3, 15, 27, 39a = 3, d = 15-3 = 12

nth terman = a + (n - 1)da54 = 3 + 53*12a54 = 639

Let mth term of an AP= 639 + 132 = 771

Then,771 = 3 + (m - 1)*12771 = 3 + 12m - 12771+9 = 12m780 = 12 mm = 780/12 = 65

Therefore 65th term is 132 more than 54th term