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Which term of the AP 150,147,144.....is it’s first negative term?

Answer»

GIVEN :

Airthemtic progression series 150,147,144,.....

To FIND :

First negative term in the series

THEORY :

{\purple{\boxed{\large{\bold{a _{n} = a + (n - 1)d}}}}}

Theory :

Given Ap series:

150,147,144,...

In this series ;

  • First term ,a = 150
  • common DIFFERENCE ,d = 147-150=-3

we have to find first negative term in the given AP series .

⇒ The value of a+(n-1) d < 0

\sf\:a+(n-1)d

\sf\:150+(n-1)(-3)

\sf150-3n +3

\sf\:153-3n

\sf3n>153

\sf\:n >\frac{153}{3}

\sf\:n>51

As n is a integer, the first value which satisfies the above condition is n =52

Now,

\sf\:a _{52} =a + (52- 1)d

\sf\:a _{52} =150+ (52- 1)(-3)

\sf\:a _{52} =150-156+3

\sf\:a _{52} =-3

Therefore first negative no is -3

\rule{200}2

More About Arithmetic Progression:

1) Genral term of an Ap

\sf\:a_n=a+(n-1)d

2)Sum of n terms of an AP given by :

\sf \: S_{n} = \dfrac{1}{2}(2a+ (n - 1)d)



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