Which one of the points 10-8i, 11+6i is closest to 1+i

1.	Which one of the points 10-8i, 11+6i is closest to 1+i
Answer» Answer: Heya.....❤✌ Let the given POINTS as A( 10-8i), B (11+6i) & C(1+i). To find which point is more closer, we have to find the DISTANCE between AC &BC. Hence, AC = √(1-10)^2 + (1+8)^2 =√162 BC = √(1-11)^2 +(1-6)^2 = √125 Here, √162> √125 So, the point B is closer to C. Hope it’s HELPFUL........ ☺

Answer»

Answer:

Heya.....❤✌

Let the given POINTS as A( 10-8i), B (11+6i)

& C(1+i).

To find which point is more closer, we have to find the DISTANCE between AC &BC.

Hence,

AC = √(1-10)^2 + (1+8)^2

=√162

BC = √(1-11)^2 +(1-6)^2

= √125

Here, √162> √125

So, the point B is closer to C.

Hope it’s HELPFUL........ ☺

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Which one of the points 10-8i, 11+6i is closest to 1+i​