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Which one of the following compounds in a peroxide?A. `KO_(2)`B. `BaO_(2)`C. `MnO_(2)`D. `NO_(2)` |
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Answer» Correct Answer - B `KO_(2)` is `K^(+)O_(2)^(-)` i.e., superoxide `BaO_(2)` is `Ba^(2+)O_(2)^(2-)` i.e., peroxide `MnO_(2)` is `Mn^(4+)O^(2-)` i.e., monoxide `NO_(2)` is `N^(4-)O^(2-)` i.e., monoxide |
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