Which one have lesser resistance A 220V , 60 W bulb or 220V , 40W bulb

1.	Which one have lesser resistance A 220V , 60 W bulb or 220V , 40W bulb
Answer» $\mathfrak{\large{\underline{\underline{Given:-}}}}$ 1 st bulb have :- Power = 60w 2 nd bulb have :- Power = 40w Potential DIFFERENCE = 220 v $\mathfrak{\large{\underline{\underline{To find:-}}}}$ Which bulb has lesser resistance=? $\mathfrak{\large{\underline{\underline{Solution :-}}}}$ For finding the resistance of both BULBS, we have to use the relation between power,resistance and voltage. It is given by formula:- ★ $\boxed{\sf{ R =\frac{ {v}^{2} }{p} }}$ Now, we can PUT the value of given quantities. Resistance of 1st bulb = $\bold{R1 = \frac{ {(220)}^{2} }{60} }$ $\implies$ $\bold{R1 =\frac{220 \times 220}{60} }$ $\implies$ $\bold{R1 = 806.67 Ω}$ Now,resistance of 2 nd bulb = $\bold{R2 = \frac{ {(220)}^{2} }{40} }$ $\implies$ $\bold{R2 = \frac{220 \times 220}{40} }$ $\implies$ $\bold{R2 = 1210 Ω}$ from above we can say that :- ★ $\boxed{\sf{ R1$ therefore, bulb 1 st has lesser resistance than bulb 2 nd.

Answer»

$\mathfrak{\large{\underline{\underline{Given:-}}}}$

1 st bulb have :-

Power = 60w

2 nd bulb have :-

Power = 40w

Potential DIFFERENCE = 220 v

$\mathfrak{\large{\underline{\underline{To find:-}}}}$

Which bulb has lesser resistance=?

$\mathfrak{\large{\underline{\underline{Solution :-}}}}$

For finding the resistance of both BULBS, we have to use the relation between power,resistance and voltage.