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Which of the following molecules geometry is true?(a) BrF5 – Triagonal pyramidal(b) ClF3 – T-shape(c) PCl5 – See-saw(d) SF4 – Triagonal bipyramidalI got this question by my college professor while I was bunking the class.Origin of the question is Valence Shell Electron Pair Repulsion (VSEPR) Theory topic in chapter Chemical Bonding and Molecular Structure of Chemistry – Class 11

Answer»

The correct choice is (b) ClF3 – T-shape

To explain: The molecule ClF5 has T-shape as it 3 bonding pairs and 2 lone pairs, so it’s true. The molecules BrF5, PCl5, and SF4 have the shapes square PYRAMIDAL, trigonal bipyramidal and see-saw respectively.



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