1.

Which of the following have identical bond order?

Answer»

`CN^(-)`
`O_(2)^(-)`
`NO^(+)`
`CN^(+)`

Solution :Both `CN^(-)` and `NO^(+)` each have 14 electrons and their electronic configuration are same.
`(SIGMA1S^(2))(sigma(1s^(2))(sigma2s^(2))(sigma*2s^(2))(sigma2p_(z)^(2))(pi2p_(x)^(2))(pi2p_(y)^(2))`
and so their bond is same i.e. 3
The NUMBER of electrons in `CN^(+)` is 12 and in `O_(2)^(-)` is 17.


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