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Which of the following has maximum mass ? (i) 0.1 mole of `KNO_(3)` (ii) `1 xx 10^(23)` molecules of `CH_(4)` (iii) `112 cm^(3)` of hydrogen at S.T.P ? |
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Answer» Correct Answer - 0.1 mole of of `KNO_(3)` has maximum mass of 10.1 g (i) Formula mass of `KNO_(3)=1 xx 39 + 1 xx 14 + 3 xx 16 = 101` 1 mole of `KNO_(3)=101 g` 0.1 mole of `KNO_(3)=(("0.1 mol"))/(("1.0 mol"))xx(101g)=10.1g` (ii) `6.022 xx 10^(23)` molecules of `CH_(4)=16 g` `1 xx 10^(23)` molecules of `CH_(4)=((1xx10^(23)"molecules"))/((6.022xx10^(23)"molecules"))xx(16g)=2.657g` (iii) `22400 cm^(3)` of `H_(2)` at S.T.P = 2g `112 cm^(3)` of `H_(2)` at S.T.P `= (("112 cm"^(3)))/(("22400 cm"^(3)))xx2g=0.01g` Thus, 0.1 mole of `KNO_(3)` has maximum mass. |
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