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Which of the following graphs correctly represents the variation of beta=-(dV//dP)//V with P for an ideal gas at constant temperature? |
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Answer»
On differentiation, we get `PdV+VdP=0` or `(dV)/(dP)=-(V)/(P)or-(dV)/(VdP)=(1)/(P)orbeta=(1)/(P)orbetaP=1` The EQUATION between `betaandP` is of the form XY = constant which represents a rectangular hyperbola. THUS, the GRAPH between `betaandP` will be a rectangular hyperbola and it is represented by (a). |
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