Which of the following are perfect square:180,2028,1458,252

1.	Which of the following are perfect square:180,2028,1458,252
Answer» Answer: Read the whole answer after which mark me brainiest or follow. Step-by-step explanation: There are some properties associated with a perfect square A perfect sq has its units digit ENDING with 0,1,4,5,6,9 not 2,3,7,8 so ii and iii 1458 & 2028 are not a perfect sqr{ending with 8} A perfect sqr has 2n no. of zeroes(even no. basically ) So i 180 is not a perfect sqr {ODD no. zero(1)} if unit digit has 4 or 6 perfect sq will have 6 as unit digit not applicable so what's applicable we can apply these for all no.s but other properties are faster..... A perfect sqr leaves 0 or 1 as a REMAINDER when divided by 3 A perfect sqr leaves 0 or 1 as a remainder when divided by 3252%3 (remainder) =0 or 1 :-D or ;-) for any perfect sqr(n+1)² - n² = n+1 +n 252² -251²= 252+251 =503 So only 252 is a perfect square roughly 15.8745078664² Make me brainliest if you want to thank me and give you answers: logical

Answer»

Answer:

Read the whole answer after which mark me brainiest or follow.

Step-by-step explanation:

There are some properties associated with a perfect square

A perfect sq has its units digit ENDING with 0,1,4,5,6,9

not 2,3,7,8

so ii and iii 1458 & 2028 are not a perfect sqr{ending with 8}

A perfect sqr has 2n no. of zeroes(even no. basically )

So i 180 is not a perfect sqr {ODD no. zero(1)}

if unit digit has 4 or 6 perfect sq will have 6 as unit digit

not applicable

so what's applicable

we can apply these for all no.s but other properties are faster.....

A perfect sqr leaves 0 or 1 as a REMAINDER when divided by 3

A perfect sqr leaves 0 or 1 as a remainder when divided by 3252%3 (remainder) =0 or 1

:-D or ;-)

for any perfect sqr(n+1)² - n² = n+1 +n

252² -251²= 252+251 =503

So only 252 is a perfect square