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Answer» a. `CH_(2)=CHCH_(3) ` b. `CH_(2)=CHCl ` c. `CH_(2)=CHC_(6)H_(5)` d. `CH_(2)=CHCOOCH_(3)` Solution :In cationic polymerisation , carbocations are formed. Greater the stability of the carbocation ,more reactive is the alkene. Since the stability of the intermediate cabocation follows the ORDER :`CH_(3)-OVERSET(+)CH_(6)H_(5) gt CH_(3) overset(+)CH_(3 ) gt CH_(3)overset(+)(C)HCl gt CH_(3)overset(+)CHCOOCH_(3)`therefore , reactivity decreases in the same order. Thus, styrene is mots reactive.
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