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which its volume Is increasing1o A ladder 5 m long is leaning against a wall The bottom of the ladder is pulledalong the ground, away from the wall, at the rate of 2cm/s. How fast is its heightthe wall decreasing when the foot of the ladder is 4 m away from the wall'? |
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Answer» length of ladder,l=5mdx/dt=-2cm/s=-0.02cm/s... (x is distance of ladder from ground)-ve sign is used because height is decreasingheight, h^2 =l^2 - x^2...... (1)from here we get h=(5^2 - 4^2)^0.5=3mdifferentiating eq. (1)2h dh/dt =0-2x dx/dt .... (length of ladder is constant so its differentiation is 0)2h dh/dt = -2x dx/dtputting values2×3 dh/dt = -2×4×(-0. 02)dh/dt=0.08/3 cm/s=8/3 m/s |
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