Which equations and/or functions represent the graphed line? Select th

1.	Which equations and/or functions represent the graphed line? Select three options. A coordinate plane with a line passing through the points, (negative 4, 0), (negative 2, 1), (0, 2), and (2, 3).
Answer» Answer: Option:-Point slope FORM : y-3=\frac{1}{2}(x-2) Slope intercept form: y=\frac{1}{2}(x)+2 STANDARD form : -x+2y=4 Step-by-step explanation: From the given graph it is clear that the line is PASSING through the POINTS, (-4, 0), (-2, 1), (0, 2), and (2, 3). If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) Let as consider any two points of the line: (2, 3) and (0, 2). The equation of line is y-3=\frac{2-3}{0-2}(x-2) y-3=\frac{1}{2}(x-2) The point slope form of the line is y-3=\frac{1}{2}(x-2). y-3=\frac{1}{2}(x)-\frac{1}{2}(2) y-3=\frac{1}{2}(x)-1 Add 3 on both sides. y=\frac{1}{2}(x)-1+3 y=\frac{1}{2}(x)+2 Therefore the slope intercept form of the line is y=\frac{1}{2}(x)+2. Multiply both sides by 2. 2y=x+4 -x+2y=4 Therefore, the standard form of the line is -x+2y=4. Explanation: mark as brainliest. plz follow me inbox me give thanks to my answer••••

Which equations and/or functions represent the graphed line? Select three options. A coordinate plane with a line passing through the points, (negative 4, 0), (negative 2, 1), (0, 2), and (2, 3).

Answer»

Answer:

Option:-Point slope FORM : y-3=\frac{1}{2}(x-2)

Slope intercept form: y=\frac{1}{2}(x)+2

STANDARD form : -x+2y=4

Step-by-step explanation:

From the given graph it is clear that the line is PASSING through the POINTS, (-4, 0), (-2, 1), (0, 2), and (2, 3).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Let as consider any two points of the line: (2, 3) and (0, 2).

The equation of line is

y-3=\frac{2-3}{0-2}(x-2)

y-3=\frac{1}{2}(x-2)

The point slope form of the line is y-3=\frac{1}{2}(x-2).

y-3=\frac{1}{2}(x)-\frac{1}{2}(2)

y-3=\frac{1}{2}(x)-1

Add 3 on both sides.

y=\frac{1}{2}(x)-1+3

y=\frac{1}{2}(x)+2

Therefore the slope intercept form of the line is y=\frac{1}{2}(x)+2.

Multiply both sides by 2.

2y=x+4

-x+2y=4

Therefore, the standard form of the line is -x+2y=4.

Explanation:

mark as brainliest.

plz follow me

inbox me

give thanks to my answer••••