Which element with last subshell to be 4s2 4p4

1.	Which element with last subshell to be 4s2 4p4
Answer» ANSWER: SE(SELENIUM) - 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^4 = 34 Se=34(ATOMIC NUMBER)

Answer»

SE(SELENIUM) - 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^4

= 34

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