1.

Which carboxylic acid `(B) (N.E = 52 gm eq^-1)` loses `CO_2` when heated to give an acid `( C) N.E = 60 gm eq^(-1)` ?

Answer» If `( C)` is monocarboxylic acid,
`N.E. (Ew) = 60`
`R - COOH = R + 45 = 60`
`:. R = 15 = CH_3`
`C = CH_3 COOH`
`(B)` has one more `(-COOH)` group which on heating loses `(-CO_2)`.
Therefore, it is malonic acid.
`((B)rArrunderset(COOH)underset(|)(CH_(2))-COOH)`
`N.E (Ew) = (Mw)/("Ionisable H atoms") = (104)/(2) = 52 gm eq.^-1`.


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