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Which carboxylic acid `(B) (N.E = 52 gm eq^-1)` loses `CO_2` when heated to give an acid `( C) N.E = 60 gm eq^(-1)` ? |
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Answer» If `( C)` is monocarboxylic acid, `N.E. (Ew) = 60` `R - COOH = R + 45 = 60` `:. R = 15 = CH_3` `C = CH_3 COOH` `(B)` has one more `(-COOH)` group which on heating loses `(-CO_2)`. Therefore, it is malonic acid. `((B)rArrunderset(COOH)underset(|)(CH_(2))-COOH)` `N.E (Ew) = (Mw)/("Ionisable H atoms") = (104)/(2) = 52 gm eq.^-1`. |
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