1.

Which among the following is (are) double displacement reaction(s)?(i) Pb + CuCl2→ PbCl2 + Cu (ii) Na2SO4 + BaCl2→ BaSO4 + 2NaCl (iii) C + O2→ CO2 (iv) CH4 + 2O2→ CO2 + 2H2O A. (i) and (iv) B. (ii) only C. (i) and (ii) D. (iii) and (iv)

Answer»

The reaction (i) is a type of displacement reaction as Pb displaces Cu and form a new compound PbCl2

The reaction (ii) is a type of double displacement reaction in which exchange of ions takes place.

The reaction (iii) is a type of combination reaction in which carbon and oxygen are combined together to form a single product that is CO2 .

The reaction (iv) is a type of exothermic reaction as the burning of natural gas (CH4 ) releases a large amount of energy



Discussion

No Comment Found