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When two uncharged metal balls of radius 0.09 mm each collide, one electron is transferred between them. The potential difference between them would be (a) 16 μV (b) 16 pV (c) 32 μV (d) 32 pV |
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Answer» Correct Answer is: (c) 32 μV Potentials of the two spheres ± e/C. ∴ potential difference = 2e/C = 2e/4πε0r = 9 x 109 2 x 1.6 x 10-19 / 9 x 10-5 V = 3.2 x 10-5 V = 32 μV. |
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