When two tuning forks A and B are sounded together, 4 beats per second are heard . The frequency of the fork B is 384 Hz. When one of the prongs of the fork A is filled and sounded with B the beat frequency increases, then the frequency of the work A is :

When two tuning forks A and B are sounded together, 4 beats per second

1.	When two tuning forks A and B are sounded together, 4 beats per second are heard . The frequency of the fork B is 384 Hz. When one of the prongs of the fork A is filled and sounded with B the beat frequency increases, then the frequency of the work A is :
Answer» 388 HZ 389 Hz 380 Hz 379 Hz. Solution :`v_(A) = V_(B) pm 4 ` `v_(A)= 384 pm 4 = 380 Hz` or 388 Hz When the prongs of tunning fork A are FILED then frequency of tunning fork INCREASES and hence beat frequency will increase if `v_(A) ` = 388 Hz. So correct choice is (a).

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When two tuning forks A and B are sounded together, 4 beats per second are heard . The frequency of the fork B is 384 Hz. When one of the prongs of the fork A is filled and sounded with B the beat frequency increases, then the frequency of the work A is :

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