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When two resistors are connected in series , their effective resistance is 80ohm.when they are connected in parallel ,their effective resistance is 20ohm .What are the valueof the two resistances?? (please give me fast ans i will follow u and mark as barnlist) please please please please please please please please please please |
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Answer» ONG>Explanation: R1=40ohms R2=40 ohms According to the QUESTION, Rs=R1+R2=80ohms(In series) therefore, R1=80-R2 Rp=1/R1+1/R2=20ohms =} R1×R2=20(R1+R2) (80-R2)×R2=20(80-R2+R2) 80R2^2-R2=1600 R2^2-80R2-1600=0 (R2-40) (R2-40)-1600=0 Therefore, R2=40ohm by R2 we GET R1 as, 40 ohms Hope it helps.... |
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