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When three identical bulbs of `60 W, 200 V` rating are connected in series to a `200 V` supply, the power drawn by them will beA. 180 wattB. 10wattC. 20 wattD. 60watt |
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Answer» If rated voltage=supply voltage then in series combination of bulbs `(1)/(P_(eq))=(1)/(P_(1))+(1)/(P_(2))+(1)/(P_(3))+`............. For this question `(1)/(P_(eq))=(1)/(60)+(1)/(60)+(1)/(60)=(3)/(60)=(1)/(20)rArrP_(eq)=20` watt |
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