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When the waves y1=A sin Wt and y2=A cos Wt are superposed, then resultant amplitude will be?????? |
| Answer» SIN wty₂ = A cos wtAfter SUPERPOSITION, the wave is given byy = y₁ + y₂⇒ y = A sin wt + A cos wt⇒ y = A [ sin wt + cos wt]⇒ y = A [ sin wt + sin (90-wt)]⇒ y = A [ 2 × sin(wt+90-wt)/2 × cos (wt-90+wt)/2]⇒ y = A [ 2 × sin 45 × cos (wt-45)]⇒ y = A [ 2/√2 × cos (90-wt)]⇒ y = √2 A cos(90-wt)⇒ y = √2 A sin wt | |